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[5xy²(x²%3xy)+(3x²y²)³...

3x²-5xy+3y² =3x²-6xy+3y²+xy =3(x²-2xy+y²)+xy =3(x-y)²+xy =3[√3+√2-(√3-√2)]^2+(√3+√2)(√3-√2) =3[√3+√2-√3+√2]^2+1 =3(2√2)^2+1 =3*8+1 =24+1 =25

-8xy²+3xy-2(xy²-xy) =-8xy²+3xy-2xy²+2xy = -10xy²+5xy = -5xy(2y-1) = -5*1/5 *(-2)*( -4-1) = 2*(-5) = -10

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