knrt.net
当前位置:首页 >> 前台js 取json 对象数组数据 >>

前台js 取json 对象数组数据

var json = { contry:{ area:{ man:"12万", women:"10万" } } };//方式一:使用eval解析 var obj = eval(json); alert(obj.constructor);alert(obj.contry.area.women); //方式二:使用Funtion函数 var strJSON = "{name:'json name'}";//得到的...

json数组用js解析并显示的方法: 假如后台返回的数据是: {'id':1,'name':'st','grant':[{'tm_id':1,'tm_name':'zc'},{'tm_id':2,'tm_name':'ww'}]} 前台获取: var data = eval_r("(" + json + ")");//json为接收的后台返回的数据; var id1 = ...

jq框架下,给个示例,仅供参考: var objs = $.parseJSON('[{"name":"aaa","age":"22"},{"name":"bbb","age":"33"}]');var str = '';$.each(objs, function(k, obj){ str += obj.name + ' is ' + obj.age + "\n";});alert(str);

二楼少了个括号 var json = eval("("+str+")");

js和java中的json对象无法互相转换的吧(用struts2可以),可以在java中将对象转换为json字符串,传到js后,再在js中将json字符串转换成json对象 Java code Map map1 = new HashMap(); Map map2 = new HashMap(); map1.put("id", 1); map1.put("...

json.a[1],还有你的这个json是有问题的,数组不要用‘’号引起来! var json={ a:["aaaaa","bbbbb","ccccc"], b:["11111","22222","33333"] };

var Data = eval('(' + json + ')');var json1 = Data.channel.item; // item是数组var r = "";for (var i = 0; i < json1.length; i++) { var obj = json1[i]; r += obj.title + "" + obj.description; var cateforys = obj.catefory; // catef...

JSONArray json = JSONArray.fromObject(models); //list集合数据转json response.getWriter().println(json);//传到前台 //ajax success: function(data){ var models = eval("("+data+")"); var rows=""; for(var i in models){ rows =rows + ...

window.onload = function () { var datanav = [{ "name": "张三", "position": "1", "powerrate": "2", "waterrate": "3", "healthcosts": "4", "watermeter": "5", "ammeter": "6", "linkman": "7", "phone": "8", "rental": "9", "tenancy": ...

网站首页 | 网站地图
All rights reserved Powered by www.knrt.net
copyright ©right 2010-2021。
内容来自网络,如有侵犯请联系客服。zhit325@qq.com