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6x 2 xy 2y 2 2x 8y 8

原式=(2x-y)(3x+2y)+2x-8y-8 2x-y -2 × 3x+2y 4 x系数-6+8=2 y系数-4-4=-8、 原式=(2x-y-2)(3x+2y+4)

原式=3x(2x-y-2)+3xy+6x+xy-2y2+2x-8y-8=3x(2x-y-2)+4xy-2y2+8x-8y-8=3x(2x-y-2)+2y(2x-y-2)+2y2+4y-2y2+8x-8y-8=3x(2x-y-2)+2y(2x-y-2)+8x-4y-8=3x(2x-y-2)+2y(2x-y-2)+4(2x-y-2)=(2x-y-2)(3x+2y+4)

6x²+xy-2y²+2x-8y-8=0 (3x+2y)(2x-y)+2x-8y-8=0 (3x+2y+4)(2x-y-2)=0 3x+2y+4=0 2x-y-2=0 解得:x=0 y=-2

3x^2+6x+3 =3(x^2+2x+1) =3(x+1)^2 x^3y-2x^2y^2+xy^3 =xy(x^2-2xy+y^2) =xy(x-y)^2 不懂可追问,有帮助请采纳,谢谢!

原式=12x2-18xy+24y2-12x2+21xy-24y2=(12x2-12x2)+(-18xy+21xy)+(24y2-24y2)=3xy,当x=73,y=-5时,原式=3×73×(-5)=-35.

方程应该是:-x³+6x²y-12xy²+8y³=0(8y³项前不应是=号,具推猜应该是+号) 将方和整理成::x³-6x²y+12xy²-8y³=0 方程两边都除以y³,整理后得:(x/y)³-6(x/y)²+12(x/y)-8=0 令x/y=...

原式=[6x3y+6x2y2-3x3y+3x2y2]÷3x2y=(3x3y+9x2y2)÷3x2y=3x3y÷3x2y+9x2y2÷3x2y=x+3y.

∵x+y=-1, ∴x4+5x3y+x2y+8x2y2+xy2+5xy3+y4, =(x4+2x2y2+y4)+5xy(x2+y2)+xy(x+y)+6x2y2, =(x2+y2)2+5xy[(x+y)2-2xy]+xy(x+y)+6x2y2, =[(x+y)2-2xy]2+5xy(1-2xy)-xy+6x2y2, =(1-2xy)2+5xy-10x2y2-xy+6x2y2, =1-4xy+4x2y2+...

﹣xy(x﹣1) 2 . ﹣x 3 y+2x 2 y﹣xy=﹣xy(x 2 ﹣2x+1)﹣﹣(提取公因式)=﹣xy(x﹣1) 2 .﹣﹣(完全平方公式)故答案为:﹣xy(x﹣1) 2 .

原式=(2x+y)()+ay-6 这个式子要能继续分解,可利用十字相乘法 2x+y 2 3x-2y -3 —————————— -6x-3y+6x-4y=-7y a=-7 或者2x+y -2 3x-2y 3 —————————— 6x+3y-6x+4y=7y a=7 △为零,似乎说法不妥,但是我们知道,一般一个二次三项式能分解成为两...

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