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Dy Dx yCotx 2xsinx 0

y'-ycotx=0 dy/dx=y*cotx 1/y*dy=cotx*dx ln|y|=ln(sin(x))+c1 y=c2*sin(x) 令 y=c(x)*sin(x) 常数变易法 y'=c(x)cos(x)+c'(x)*sin(x) y'-y=c(x)cos(x)+c'(x)*sin(x)-c(x)cos(x)=2x*sin(x) => c'(x)=2x => c(x)=x^2 + c3 即y'-ycotx=2xsinx的通...

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