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F3x4+2x2/x2+1Dx

4-2x3-2x2+2x+1=x4-2x3-3x2+x2+2x+1=x2(x2-2x-3)+(x+1)2=x2(x+1)(x-3)+(x+1)2=(x+1)[x2(x-3)+x+1]=(x+1)(x3-3x2+x+1).

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