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jAvA Json 串中的转义字符

一:解析普通json 1:不带转化字符 格式{"type":"ONLINE_SHIPS","message":{"currentTime":1400077615368,"direction":0,"id":1,"latitude":29.5506,"longitude":106.6466}} JSONObject jsonObject = new JSONObject(jsonstr).getJSONObject("me...

一:解析普通json 1:不带转化字符 格式{"type":"ONLINE_SHIPS","message":{"currentTime":1400077615368,"direction":0,"id":1,"latitude":29.5506,"longitude":106.6466}} JSONObject jsonObject = new JSONObject(jsonstr).getJSONObject("me...

我上周也因为这个replace纠结过,后来找到答案,\/这在内存里就算一个字符,replace没用的。想想别的方法吧

你要字符串转json格式,还是json转字符串? JSONObject json_result = new JSONObject(); json_result.put("userId",""); JSONObject initParame = new JSONObject(); initParame.put("contextConfigLocation", "cfl"); json_result.put("initPa...

你是想要这种结果么 {"id":"无数据","name":"无数据","a":"无数据","time":"getData()"}

使用如下代码 objectMapper.configure(Feature.ALLOW_UNQUOTED_CONTROL_CHARS, true) ;

可以参照如图的例子:

var isArray = function(json) { return Object.prototype.toString.call(json) === "[object Array]" ? true : false;}var json = {}; // 获取到的json对象或者json数组var yugi = function(json) { if (isArray(json)) { for (var i = 0; i < ...

一:解析普通json 1:不带转化字符 格式{"type":"ONLINE_SHIPS","message":{"currentTime":1400077615368,"direction":0,"id":1,"latitude":29.5506,"longitude":106.6466}} JSONObject jsonObject = new JSONObject(jsonstr).getJSONObject("me...

一:解析普通json 1:不带转化字符 格式{"type":"ONLINE_SHIPS","message":{"currentTime":1400077615368,"direction":0,"id":1,"latitude":29.5506,"longitude":106.6466}} JSONObject jsonObject = new JSONObject(jsonstr).getJSONObject("me...

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