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sql 时分秒查询

select convert(varchar,GETDATE(),108),right(CONVERT(varchar,getdate(),120),8) 里面有两种方法都可以

那就做成存储过程,或者函数; 传入参数是 日期开始和结束时间 然后循环调用这个函数或者存储过程,每次查询一天,然后在下一轮循环时 加 1 天。

declare @date varchar(20) set @date = '2013-06-06 13:30:25' +'%' SELECT * FROM TELEPHONE_HISTORY WHERE CONVERT(VARCHAR(20) ,RECVTIME , 120) LIKE @date 其中:CONVERT(VARCHAR(20) ,RECVTIME , 120) 就是将日期 类型转 “YYYY-MM-DD HH:...

select * from tabnamewhere dtcol >= '2014-08-01 00:00:00' and dtcol

转换一下即可: sqlserver: select * from tab where convert(varchar(10),datecol,120) between '2013-04-15' and '2013-05-04' oracle select * from tabxxx where to_char(datecol,'yyyy-mm-dd') between '2013-04-15' and '2013-05-04'

可用函数datename 返回代表指定时间字段的小时和分钟。SELECT datename(Hour Hh h, '2017-10-15 10:30:00') --返回:10,即10小时。SELECT datename(Minute Mi n, '2017-10-15 10:30:00') --返回:30,即30分钟。 拓展资料: 1、SQL语言,是结构...

select distinct Convert(varchar(10),orderdate,120) as "672" from d_orderdetail inner join D_Order on D_Order.orderid=d_orderdetail.orderid where (productid=672) and (Convert(varchar(10),orderdate,120) between '2004-07-01' and '...

select * from table where CDate(Format(年月日,"yyyy-mm-dd")+时分秒)>CDate('2012-01-01 19:00:00') and CDate(Format(年月日,"yyyy-mm-dd")+时分秒)

select GETDATE() as '当前日期', DateName(year,GetDate()) as '年', DateName(month,GetDate()) as '月', DateName(day,GetDate()) as '日', DateName(dw,GetDate()) as '星期', DateName(week,GetDate()) as '周数', DateName(hour,GetDate()...

--取'2016-10-18'这天的数据 Select * From case_col_rec Where cast(col_time as date)='2016-10-18' 如果你只是要取某天的数据,不建议你转换数据类型後来匹配,因为那样不会走索引 Select * From case_col_rec Where col_time>='2016-10-18' A...

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